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(3x-5)(5-3x)+5(x+1)^2=30
We move all terms to the left:
(3x-5)(5-3x)+5(x+1)^2-(30)=0
We add all the numbers together, and all the variables
(3x-5)(-3x+5)+5(x+1)^2-30=0
We multiply parentheses ..
(-9x^2+15x+15x-25)+5(x+1)^2-30=0
We get rid of parentheses
-9x^2+15x+15x+5(x+1)^2-25-30=0
We add all the numbers together, and all the variables
-9x^2+30x+5(x+1)^2-55=0
We move all terms containing x to the left, all other terms to the right
-9x^2+30x+5(x+1)^2=55
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